A(x)=25x^2

Solution for A(x)=25x^2 equation:

(A)=25A^2

We move all terms to the left:

(A)-(25A^2)=0

determiningTheFunctionDomain
-25A^2+A=0

a = -25; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-25)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-25}=\frac{-2}{-50}
=1/25
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-25}=\frac{0}{-50}
=0
$